e^3x/e^4=17

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Solution for e^3x/e^4=17 equation: 


D( x )

e^4 = 0

e^4 = 0

e^4 = 0

e^4 = 0

x belongs to the empty set

x in (-oo:+oo)

(e^3*x)/(e^4) = 17 // - 17

(e^3*x)/(e^4)-17 = 0

e^-1*x-17 = 0 // + 17

e^-1*x = 17 // : e^-1

x = 17/(e^-1)

x = 17/(e^-1)

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